| Author | Maths Problems |
|---|
| (a-m)(b-m)(c-m)(d-m)............(z-m)=? |
1. There are 2 doors. One leads to heaven and other to hell. Each door is guarded by a keeper. One tells truth while other always lies. U can ask 1 question in total to one of them. U need to go to heaven, what question would u ask?
2. A landlord owns 3 houses each has a tenant. The rent is 25 gold per month. The landlord asks the watchman to collect the rent. Landlord takes 70 gold and gives 5 to the watchman. The watchman in return keeps 2 gold and distributes 1 gold to each tenant.
Now the rent is 24 gold per house= 72 gold, watchman has 2 gold. Where is the missing 1 gold? |
#81
0
(m-m)? XD
#82
1.???
2.rent is 24 gold per house= 72 gold, which includes money to guard.
[70(to tenant)+2(guard)]=72(effective total rent):)
Where is the missing 1 gold?
Actually its missing 3 gold which is returned to them by the guard:) |
Now the rent is 24 gold per house= 72 gold, watchman has 2 gold. Where is the missing 1 gold?
watchman has 2 gold and landlord has 70, 70+2=72, no gold is missing :P |
1. There are 2 doors. One leads to heaven and other to hell. Each door is guarded by a keeper. One tells truth while other always lies. U can ask 1 question in total to one of them. U need to go to heaven, what question would u ask?
you can ask either one of them: "what will the answer be if I ask the other guard?". If the answer is "hell" then that gate will actually be heaven and if the answer is "heaven" then that gate will actually be hell. |
There's also a trickier version of 2-doors problem:
"An explorer reaches a cross-road where one path leads to the the village, in which food and refuge await, and one to the jungle, where he would be torn to bits by wild animals. Three men are standing at the cross-road, a liar, a truth teller and an idiot. The latter answers yes or no completely at random, whatever you ask him. You have two yes-no questions to find the path to the village." (quoted from chessbase.com) |
Here is one question.
I wanted to buy a 97$ shirt, but doesnt have enough money. So I borrowed 50$ from dad and 50$ from mum. I bought the shirt and the cashier gave me 3$. I kept 1$ and give back 1$ to mum and dad respectively. I now owed my mum and dad 49$ respectively. But when added up, 49+49+1 is only 99.
Where is my one dollar?
PS: I don't know the answer |
for Lord spiral-doom: I remember this being a mind-game to keep people thinking. Was developed by newton.
49 + 49+1 is not supposed to give any result. its just a sum of three numbers being used in the question.
49 is the amount u owe to parents, which is wrong, as u kept 1 dollar of theirs. so u owe them 49.5$ |
| (2^n)-7=x^2. |
| x=3 , n=4 |
for Anony-mouse:
thanks for info
it happens to my friend =) |
Solve This :
In How many ways can the number 80 be written as a sum of two primes? |
#88: 49 + 49+1 is not supposed to give any result. its just a sum of three numbers being used in the question.
49 is the amount u owe to parents, which is wrong, as u kept 1 dollar of theirs. so u owe them 49.5$
You claim to know this kind of mind-game and still think that you owe the parents $49.5?
Please also observe the forum rules:
2.4. Users of low literacy are recommended to compose messages in a text processor with spelling check. Messages should contain proper punctuation and capitalization to make it easy to understand the content. Extensive use of short forms such as "u" instead of "you" is prohibited. |
for Lord STB:
Actually I dont know the answer. It happens in real life. My friend is making a fuss about it.And its why i post it.I just hope someone knew why and anony-mouse happens to know it. Like i stated earlier, i said i did not even know the answer. =) |
| I correct my question it is actually that in how many ways can number 80 be expressed as sum of primes |
for VRBack: as a sum of two primes
7,73
13,67
19,61
37,43
as sum of primes, Have no clue whatsoever |
Try out..
one more in how many ways can six numbers (123456)be arranged on six faces of a cube |
#97:
I would think in 30 different ways. Interesting problem.
#94:
My point was that Anony-mouse did not know the answer. He is right that 49+49+1 is a nonsense sum.
You owe the parents 49+49=98.
You paid 97 and saved 1 =98.
#95:
Unfortunately, I think it is impossible to make an analytical answer so it must be numerical. I'm not bored enough to try all the numbers one by one. It must be a rather large number of sums. |
1. for which n this equation is right:
a^n + b^n = c^n (a,b,c,n are naturals)
2. pi = a_0 + a_1*x + a_2*x^2 + a_3*x^3 + ... + a_n*x^n
is this assertion right ?
3. P != NP ? (not easy question) |
for VRBack:
for 97
I think it would be 6! = 720. not sure though |
