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How do you know how many waves will be there in a certain Conspirator? Is it random or something like-
{x} + y?
it depends on level of difficulty
It is not random but it differs by level and type.
for wiz_king:
for joechue:

x stands for the difficulty level...
I know. But, there is no formula as it differs for each type. You can't just add a constant that can be used for every type.
I think it is x +1
{0} = 4 waves https://www.lordswm.com/war.php?warid=484537439&lt=-1
{0} = 7 waves https://www.lordswm.com/war.php?warid=484546515&lt=-1
{0} = 5 waves https://www.lordswm.com/war.php?warid=484486841&lt=-1
{0} = 4 waves https://www.lordswm.com/war.php?warid=484694323&lt=-1
{0} = 5 waves https://www.lordswm.com/war.php?warid=484715468&lt=-1
{0} = 5 waves https://www.lordswm.com/war.php?warid=484802771&lt=-1
I have counted waves on higher levels and i have seen that it is x +1 I dont know about the lower levels
no you are just talking random nonsense
its something like (x/y +y)y/x where x is the difficulty level and y is
attempt number
no

all links above were first attempt
@10

Your formula is absurd. It says that it gets more and more difficult on retries.
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