| Author | seduction |
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Seduction:
α Activated special ability.
This creature can hypnotize any enemy stack once per battle provided it’s not immune to mind-affecting effects.
how to calc which stack it can control |
as far as i know
hp of stack shouldnt be more than 4 times hp of temptress |
| great barb it work this way when you seduce one creature less hp that stack have you will control it longer but if creature have am not sure if its 8 times or maybe 4 times bigger hp you can,t even seduce it... |
The formula is T={2+log(2)[HPtemp/HPtarget]} turns, Te(0;4]
Good luck calculating it in combat :-P |
| Well artic that formula is so messed up yay someone could make it even longer... |
| So according to that you can control the target stack for at least 2 full turns regardless of temptresses hp and target hp? |
| Nope. log(2)[HPtemp/HPtarget] can be negative :p |
| Oh oops my bad. Forgot my basic math lol |
Nope. log(2)[HPtemp/HPtarget] can be negative :p
Ofc it can be negative couse then target have higher hp then temptress :) or am i wrong? |
| #9 Target will not even be seduced it will waste of turn or the temptresses if it is more than 4*hp of T |
| [Post deleted by moderator Dragon Eater // T cannot be negative, because of the domain of the formula] |
The logarithm can be negative.
It will not be wasted, the minimum is 0.1.
you can put Te[0.1,4] |
If The formula is T={2+log(2)[HPtemp/HPtarget]}
and the taget stack has 4 times hp , Then
T= 2 + Log(2)(1/4) = 2-0.3 = 1.7 turns?
please correct me . |
Logarithm with base 2 of 0.25 is the power you need to put 2 in to get 1/4.
I believe that power is -2, why -0.3?
2^(-2)=1/(2^2)=1/4.
so if the target stack has 4 times or more the hp of temptresses, the duration of hypnosis will be minimal. |
| Yay what an mathematician |
@arctic...
Okay, i did log {2*(1/4)} = log of 1/2 = -0.3
my bad,didnt know the (2)meant base, i was taking base 10, i get it now :) |
| QATC. |
| closed by Arctic (2013-02-19 10:43:17) |
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