| Author | Do items 0/25 and 0/1 cost the same price (in inventory)? |
|---|
Do items 0/25 and 0/1 cost the same price (in inventory, i.e. when you sell them there)?
I know that item 0/25 costs about 65% of item 25/25 value: |
Do items 0/25 and 0/1 cost the same price (in inventory, i.e. when you sell them there)?
No
% of cost you get back (when selling a repaired item) = 65%*(durability)/(original durability), no less that 25% |
| https://www.lordswm.com/help.php?section=39 |
Thank you for too quick answer :)
Are you sure? Where did you get that information? |
| [Post deleted by moderator Shebali // ] |
| https://www.lordswm.com/forum_messages.php?tid=1844882 |
And since sell price isn't always 65% of unused item value, it never hurts to check it. For example, here:
https://www.lordswm.com/photo_pl_photos.php?aid=789 |
Thank you for a really useful information.
Actually I need more general formula.
For example, I have two Rings of inspiration (3/18 and 12/18).
Both of them have the same price and repair price:
Price = 4000 gold + 1 Crystals + 1 Gems = 4738 gold
Repair price = 1888 gold = 4720*0.4 (not 4738*0.4 gold ?)
Inventory price for 12/18 ring = 3697 gold
Inventory price for 3/18 ring = 3223 gold
How do I get numbers 3697 and 3223 from your formula? |
Price = 4000 gold + 1 Crystals + 1 Gems = 4738 gold
Repair price = 1888 gold = 4720*0.4 (not 4738*0.4 gold ?)
The system prices for resources are 180 for wood and ore; 360 for other.
How do I get numbers 3697 and 3223 from your formula?
You don't. If you look closely enough, you'll realize that it the formula calculates a different thing. |
For Rings of inspiration (3/18 and 12/18) inventory sell price is somewhere between 80% and 65% of unused item cost
But you asked for 0/x-n sell price. I gave you a formula for that one. |
Thanks.
Now I undrestand this (correct me if I'm wrong):
Inventory price for item 0/x (when the new item is n/n, i.e. x=n is the maximum) is this:
Inventory_price = max(0.65*(x/n),0.25)*new_item_price
Let take Ring of inspiration as an example:
new_item_price = 4000 gold + 1 Crystals + 1 Gems = 4720
n = original durability = 18
So
(0/1) Inventory_price = max(0.65*(0/18),0.25)*4720 = 0.25*4720 = 1180
...
(0/6) Inventory_price = max(0.65*(6/18),0.25)*4720 = 0.25*4720 = 1180
(0/7) Inventory_price = max(0.65*(7/18),0.25)*4720 = 0.65*(7/18)*4720 = 1193
(0/8) Inventory_price = max(0.65*(8/18),0.25)*4720 = 0.65*(8/18)*4720 = 1363
...
(0/x) Inventory_price = max(0.65*(x/18),0.25)*4720 = 0.65*(x/18)*4720 = 170.44*x
...
(0/18) Inventory_price = max(0.65*(18/18),0.25)*4720 = 0.65*4720 = 3068
Right? |
Right?
I believe so, yes. |
Yesterday I've made some calculations here (in 11th post):
https://www.lordswm.com/forum_messages.php?tid=1846583
I've got approximate formula for Rings of inspiration y/18 (i.e. 0/18,1/18,...,18/18):
Inventory_price = (158/3) * y + 3065
I'm sure there is somewhere the general formula for items y/x, where y in {0,1,...,x} and x in {1,2,...,n}. |
Just wanted to tell you that finally I've made EXACT calculations for Steel Blade:
https://www.lordswm.com/forum_messages.php?tid=1846583
(in 12th post)
I asked Arctic to review those calculations and he said:
"The calculations in post 12 are perfectly correct =) Nice job, I hope there would be people who'd appreciate your work in there =)" |
